Stack overflow all customers. You should be able to pass in a list of customers.

Stack overflow all customers org = We have a need to know which database architecture makes more sense to use and why. Specifically, those that have open orders with either prepay or 10n30 and at least one normal order. So, Both first and last names can be specified together. id, cr. I am trying to dynamically get a count at a per month basis per customer and type. The source account has all the customer, card, and charge data. To learn more, see our tips on writing great Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; How to select all customers and the latest order for each of them. name)a print @columnnumber -- Compose the column names for Pivot declare To access all tenants with the same application, check the below: Assuming your tenant as TenantA and customer tenant as CustomerTenant. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I have to extract all those customer names having transactions of less than 5000 each per month for 6 consecutive months and then have 3 transactions of 20,000 each on 7th month. Here the function that called from the client when I use the above object. This works by moving the check on warranty_expiry from the where clause to the having clause, as follows:. unitcost*lineitems. Read. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Since you want to have all customers to be visible, you need to have them in your query. Now all See why thousands of companies around the world rely on Stack Overflow for Teams to enable their developers and help their teams to focus on what matters most. for each customer. Wishlist : Customer_ID, Created_Date, Product_ID Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; I am trying to get all customers from QuickBooks 2012 desktop using QBWebConnector. id) = 1; Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; Find all payment option , c, e, m. Making statements based on opinion; back them up with references or personal experience. This will allow the person on the other side of the pipeline to identify the issues. Category C I like to approach this type of question using group by and a having clause. customerID, c1. count) from ( select c. CustID WHERE Product in (SELECT Item FROM Product WHERE (Item = 'Toaster' AND Item != 'Breadbox')); Thanks for contributing an answer to Stack customer firstname customer lastname. customer_id ORDER BY o. Following is the table structure: Customer to Order is one to many Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; I try to get Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; I'm having trouble coming up with a query that will find all customers who have purchased both PROD1 and PROD2. id = Where I need to get the names of all the unique customers who have spent more than 1200. api / debtlist form. In Python, you could do something like this: customer_id I have two MySQL tables, tblclients and tblservices. customer_id, o. All the common parts used for all customers should work on shared/develop branch. and so on; My database look like For each customer, I want to return: id, name, total_orders, total_value Customers: ╔════╦═════════════╗ ║ ID ║ NAME ║ ╠════╬═════════════╣ ║ 1 ║ John Smith ║ ║ 2 ║ Jim Jimmers ║ ╚════╩ All customers are hosted under 1 unique database under which all customers all have 1 table per feed - in that case, 1 customer can have 2 tables if he as 2 different product feed. select c. I have added Status value In Power BI Slicer Visual to filter the Matrix Data. SELECT city ,group_concat(customerName) as all_customer FROM customers group by city Jeff Attwood lists 4 ways that Stack Exchange makes money (mostly, advertising, SO for Teams, and Stack Overflow Jobs). 1 and given a table payments with columns customerid,paymentdate i need the all customers latest payment. cid,c. cust_id) I am trying to find the customer count (monthly) and their purchase frequencies (all-time) between March 2020-March 2021. Customers -> Organisations -> linked through rel_customer_addresses to address table. All the feature development just for the customerN should work on its own customerN/develop branch. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; I need a way to log out all signed in customers from my Prestashop site, as a domain name migration caused some issues with user sessions, and having customers sign out and re-sign in is fixing it. branchNumber FROM Customer c2 join Owns o2 on You want conditional aggregation: SELECT c. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; I am trying to get all continuous period of customers from their contract start and end dates in Synapse SQL allowing up to 30 break between contracts. I would like to print all customers from may, april, juni, july and so on. At the moment I'd like to support credit cards and bank accounts (SEPA). customer_id = c. ORG, c. I am writing a query to delete all customers which never ordered, I am getting below error, Unknown table 'customers' in MULTI DELETE. Current Example (categories ranked against each other for the given customer) Customer A. I have a table in SQL Server that contains customers' transactions From 2022-02-10 to 2022-03-10. How it should read, if compared against all customers (each category is ranked for that given category vs all other customers not selected) Customer A: Category A: 124. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; This will DELETE all customer data including logs. Here are my tables (left irrelevant columns out its default open cart if that helps): Customer. custPhone ORDER BY custPhone, custName Pro tip Avoid mixed case in database, table, and column names. Follow edited Jun 5, 2020 at 11:45. Provide details and share your research! Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; I need to write a SQL statement that gets all Orders of Customers who are assigned to the current logged in user (by agent_id) and has this tag (ID: 234) but not any of these tags [3343, 445, 333] and has purchased any of these product (IDs: 18 Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; Display all customer info for customers with at least 2 orders. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; You can optionally request that the response include the total count of all customers that match your filters. For Example, in ruby you can do it as follows: customers = Stripe::Customer. Like first 6 rows with 5232 are Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; DateOfPurchase. Through Prestashop admin panel, it’s not possible to export all customers data, so you need to write custom SQL query to select all customer data in PHPMYADMIN and export CSV sheet. Provide details and share your research! Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question. The tables concerned have the following simplified shape : Sales : {SaleID, CustomerID, Amount}Customers : {CustomerID, CustomerName}This query gives me what I want, but I think having to compute the SUM twice is a sign that I'm perhaps not approaching this problem Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; This API can list all the subscriptions for a SINGLE customer. ID, Customer. order_products. Just select the distinct states from that table. So I have tried the following: SELECT * FROM Customer JOIN Product ON Customer. cid = o. It reduces the portability of your data from one server to another. birthDate FROM Customer c1 join Owns o1 on c1. Customer(Customer ID, name) Order(order ID, Customer ID) Olines (order ID, Store ID, toy ID) I want to write a query in SQL to find customer Id of all customers who have all their orders with just one store and that store cannot be 'Toys R Us'. id FROM customers LEFT JOIN orders ON orders. Created a multi-tenant application in TenantA by selecting "Accounts in any organizational directory (Any Microsoft Entra ID tenant - Multitenant)" and grant User. SET FOREIGN_KEY_CHECKS=0; -- reset customers TRUNCATE customer_address_entity; TRUNCATE customer_address_entity_datetime; TRUNCATE Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; I want to make a separate inquiry screen and list the debts of all customers. Category B: 2. ) Users -> Tenants -> linked through rel_users_addresses to the address table (as 1 user could have delivery_address, invoice address etc. customerID = o1. DELETE customers FROM customers as c LEFT JOIN orders as o ON c. g. Expected result is : Customer_no = (1,2). js. gt. optional. We have a list of customers who are all going to use the same table structure (with Shopify has a nice API module for Node. ), then this one property called Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company SELECT c1. customers_id IS You are right, you must write a naive loop with a cursor per the stripe docs:. Each record in tblservices represents a service we provide for a client and there can be many services per client. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; there are a number of requirements to be considered before you place all the customers in a single larger DB: Security: Whilst you have the data in a single database you have no isolation protection for the data, e. I have the table of customers with different statuses in different months . Example: Considering customer A, Information for the customer will be stored as follows: Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I have database with Customers. This is my query : Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Important: The application contains master data which is shared across all customers (e. firstname, Customers. timestamp FROM customers c CROSS JOIN LATERAL ( SELECT timestamp FROM customer_orders o WHERE o. so a table with entries. s_company); SELECT Orders. List all customers that made at least 2 purchases in any period of six months. The next order from the same customer is on 2023-06-29 and 2023 Ideally, you have a table customers with exactly one row per relevant customer_id. is a "customer" someone ordering comfy Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; @zahidhasanemon yes i want the admin to view all orders made by all customers – Mariem. custPhone = multiple. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, all the customers that purchased more than 2 items in one order, and the name of the salesman in charge; Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; Since customer with customerid 4 has ordered from 2023-06-24 to 2023-06-27. Provide details and share your research! I have a wcf service that I keep him Dictionary. How would I query for only customers that have done business with all three customers before? Sample Table. lastName, Customer. Commented Nov 5, 2019 at 8:10 @N69S i tried to follow a tutorial but i didn't get it well as i'm new to laravel. I am new to SQL and not sure how to go about this. – David דודו Markovitz. product_name, Customers. SELECT customer_client. Data Two tables: Customers and Orders. The ListCustomers endpoint only seems to return customers "created by you", whereas the vast majority of my customers were created by Square. All the transactions for a customer will be stored in different rows. level, customer_client. private Dictionary<string, string> MyDic= new Dictionary<string, string>(); Any call I done the dictionary cleared. I'd like to retrieve the customers (ID and name) who have spent at least $1000. id_customer, count(*) from customer_product cp join customer_product cp2 on Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company , where Customer 1 and Customer 2 have their own admin accounts I need to show all customers that a user has access to on a widget. My request QBXML is as follows I am looking for most efficient query to fetch Customer name who have either paid for all the orders they have placed with us or have not placed order at all. I have tried the option below for getting page-wise 250 records at a time. CustomerName AS Customer, CASE WHEN COUNT(CASE WHEN i. Category D: 4. – Tom3652. How can i find who use all payment method and show their names I tried SELECT cr. Below is the table. So far I have: SELECT customers. The problem is that I can not make a correct alias for a widget to get "all my customers" as a list. e. loan_number AND branch_name Create a Dashboard as template you would like to share to other customers; Define dynamic entity aliases which would work with different customers (e. all devices with type "thermometer" --> avoid single Device IDs) Place the Dashboard in a Dashboard Group; Share the Group with the Customer of your choice (read, write or custom access) Question Find customers who have never made an order. I want this object to be recognized in all of the calls to all the customers as one object. the SQL query that I wrote is . Now I want to write a query which will find the customer_no having all phone_no=(11,12,13). Can someone tell me what would be a query to Invoice ===== InvoiceID CustomerID InvoiceDate TransactionDate InvoiceTotal Customer ===== CustomerID CustomerName What I want is a listing of all invoices where there is more than one per customer. (B) Use a separate database for each customer with all of the needed tables &c. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; I have searched for getting all customer one by one. Customers are completely separate and billing needs to be very distinct; In the above scenario, I would set up different tenants for each 'customer'. There are three different company that the customers could have done business with A, B, C. SELECT distinct customer_name FROM borrower, loan WHERE borrower. I am ultimately trying to find the percentage of people who order more than twice, but I want to exclude the customers who were new in 2016. id; Expected result: Show the list of all products' names ordered along with (for this customer the default customer level is 8, so looking for blvl = 8 and customer = lvlholder) All the "level prices" from 1-8 are stored in a lvlholder customer but have multiple price records so I need to pull the latest date for those. Commented Jun 26, 2018 at 13:09. I was referring here. cs, Sales Here I'm stuck how to Generate All customers total Sales Statement. You can then go through the order's items attribute to find the SKUs included in the order. customerID join Account a1 on a1. 1" and "Child To determine bulk customers (customers who purchase, let's say, 5 products or more in a single transaction), where each row represents a unique transaction with a unique timestamp. cid group by c. id = ii. s_id = o. CREATE TABLE `customers` ( `customerNumber` int(11) NOT NULL, `customerName` varchar(50) NOT NULL, `contactLastName` varchar(50) NOT NULL, `contactFirstName` varchar(50) NOT NULL, `phone` varchar(50) NOT NULL, `addressLine1` varchar(50) NOT I want to make a sql for statistic over customers. id HAVING COUNT(orders. This means that every row in the left table will be returned whether it has a match on the right table or not. Customer 1 should see "Child 1. id=orders. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; I am working on a database and I would like to get the list of all the customers that bought a product with a name containing citroen but none with a Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company SELECT Customer. Provide details and share your research! Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; im using Mysql 5. warranty_expiry >= NOW()) = 0 Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Visit the blog Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Try this if you use MS SQL Server:-- 1st, get the number of columns declare @columnnumber int = 1 select @columnnumber = max(a. The destination account has the copied card and customer data done by Stripe Support. descriptive_name, In the above result I want to list all order dates and count the number of customers distinct per fiscal year. Improve this question. customerId = customers. 4. Either first or last name alone can be specified by the user. Follow Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question. resource_name, customer_client. To do so, specify include[]=total_count in your request. I have a requirement to call Stripe List All Customers API. row, customerid, paymentdate 1 5 2011-03-01 2 5 2011-04-01 3 6 2011-01-01 4 7 2011-01-01 5 7 I want to find ALL pairs of customers where the second customer in the pair has purchased AT LEAST all of the products that the first customer in the pair has purchased. I'm making use of two tables, Orders and Order_rank. I need to make continual fetches 100 customers at a time. Any help would appreciated. ordNum . Follow asked May 16, 2017 at 17:43. ID Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; It is like all the items bought by a certain customer at certain day will be all continuous and if the customer comes and buy items again after some customer id then it is considered as a different day. ID = CUSTOMER. I need to get result consisting all customers and their last order. Your Customer INNER JOIN Orders will prevent that since it will only get customers that have an order. Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question. accNumber join Branch b1 on b1. You can get the list of customers using: select o. invoices The customer number is common to both tables and I need to pull the customer number and name the customer table has a invoice date so i could look for that and the sales table has a status column that includes closed and open status's and a date printed column. It should be note that all the customers' branches should merge from shared/develop branch before a new feature coding. You may want to filter out NULL if the customerstate column is nullable (WHERE CustomerState IS NOT NULL). If you don't want 0 counts, then change to an INNER JOIN. Thanks for contributing an answer to Stack Overflow! Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, I am able to show all customer details(in admin page) and all products for a customer to browse through. It then finds the customer data from the destination account using the collection of customer/card data from the source. Then: SELECT c. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; But instead of getting the list of orders for each customer, get the list of all orders for all customers that you need in one pull. Additionally, you should use explicit JOIN and not the old-style syntax: c. e :- MONTH(NOW()). firstName FROM CUSTOMER INNER JOIN has ON has. customers_id WHERE o. A cursor for use in pagination. Here's a pseudo-query that kind of looks like what I want to do: (obviously this wouldn't work) Stripe::Invoice. API Support & Training To get only the customers with order, use an INNER JOIN. timestamp LIMIT 3 ) o ORDER BY 1, 2; fiddle Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; NW_customers is not needed at all if you wish to retrieve only the customerid since only a customer with orders might have placed an above average number of orders. Root Customer must see Customer 1 and Customer 2 and their children. To get only the customers with order, use an INNER JOIN. id_customer, cp2. if I will get that how to generate customers total sales I Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; These are 3 tables that I have and Im getting the query for all customers (ID, Email, Name) who have spent above X If you still wish to do that, What you can do instead is to get a list of all the customer and filter on the response you get using email. I'm trying to pull a list of all open orders from a customer where the same customer has used both one of our special payment types as well as one of our standard options. You should be able to pass in a list of customers. orderdate) as count from customer_table c join order_table o on c. id from customer c inner join invoice i on c. So, in the example tables below I would want to return order_id 1, 3, and 4. I want any orders they placed after 2015 too, but I DON'T want the records for customers whose first order was in 2016. Additionally, you should use explicit JOIN and not the old-style syntax:. s_id group by c_id having min(s. All customers are hosted under 1 unique database, HOWEVER, in this 3rd solution, we only have 1 unique table that host all products feed of all customers. ID, c. Add a comment | 1 Answer Thanks for contributing an answer to Stack Overflow! I am trying to SELECT customers who are over the age of 65, and also have a balance greater than 5000. CustID=Product. A customer and an order have both a linked Customer_ID. invoices. It looks like like calling all on invoices overrides the previous query where it retrieves the invoices for the customer. Select customer_ID, Count(*) FROM reviews WHERE customer_ID in ( Select Customer_ID from reviews where products_id = '170') Group By customer_ID This should give you a list of all CustomerID's along with the Count of all their reviews, but it will limit it only to the customers who have left a review for product 170. (as 1 customer could have delivery_address, invoice address etc. a customer can have more than one debt record. Im working on sample data, there Today we released Unified Search, which allows Enterprise plan customers of Stack Overflow for Teams to search for answers from both their private instance and public content from stackoverflow. Here, am trying to implement a query to get all customers when firstName and/or lastName is specified. from 2020-03 til 2021-02). Right above, it only shows one rep and counted all the customers in that table. lastName FROM customer cr INNER JOIN purchase pm ON (cr. mysql; sql; database; sum; having-clause; Share. * FROM Customer JOIN ( SELECT custPhone FROM Customer GROUP BY custPhone HAVING COUNT(*) > 1 ) multiple ON Customer. You may assume the table has the data for the last 10 years. Where two of the counts are the first time we got an order based on the program and the other two are programs/customers we lost based on their . it is co-located. customer_id inner join invoice_item ii on i. Output the first name of the customer. The last order could be by ID (ID is incremental) or Timestamp (DateTime field). Category B: 15. This is my code: SELECT Customer. The customers who have not placed order should be also in the result. And when, selecting for example A, it only shows customers who has A Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I have two tables "OEHR_Orders" and "OEHR_Customers". I found out that this is a killer to maintain many websites so I decided to place the source files of the webshop in a common place in the server and create an alias on the (1) Add a CustomerId column to Customers and manage all of the implications of multiple customers playing in the same pool. id = i. SELECT first_name from customers WHERE first_name not in (select first_name from customers join orders on customers. Also, there is no PK or unique value. it is working via curl if I pass the value like this below-d limit=3 \ -d created[gt]= 1599709192447\ -G I'm trying to find out which customers have made 2 consecutive orders at a restaurant. Even if you initialize the dao in it with. I am sure this is all I would need to put it together but am stumped as to how. SELECT c. That being said, here's a very central question: who does Stack Our team has years of expertise on community building and helping our customers integrate workflows and APIs, customize onboarding and training, and build bespoke internal marketing programs. customer_id order_id date_added. I can not figure out how to successfully calculate their age in my WHERE clause. quantity) AS "total_spent" FROM orders I want to select all records for customers whose first order is from 2015. Table names are: customers (10 records) and orders (20 records) I've tried this code, but it doesn't Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Hibernate, Java 11]. " I can not edit yet question, but someone who has got more reputation than me, could this. invoice_id group by c. As it stands your question is not really about programming and far too vague to answer, e. therefore, I want to show the total debt, total received and remaining debt amounts of each Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, I need to find the names and total spend of all customers that made more than one order. ItemName = 'fork' THEN 1 END) > 0 THEN 'Y' ELSE 'N' END AS Fork, CASE WHEN COUNT(CASE WHEN i. MONTH(created) != MONTH(NOW()) will filter out the customers whose created date's month is not equal to current month and YEAR(created) = YEAR(NOW()) will filter out the current Year SELECT * FROM customers WHERE deleted = 0 and MONTH(created) != MONTH(NOW()) Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; I am trying to compile a list of all customers using the Stripe Node API. Finally, you can use a SKU's product attribute to retrieve the product associated to the SKU. id having max(ii. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; I have to find out Find the list of all the customers with a name that contains a letter between “a” and “d” as the second letter. my query is not working as needed. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; For instance, the following gets all customers that have purchased a similar product as another, ordered by the number of similar products: select cp. email == "[email protected]" end I am not familiar with the REST API aspect, but if you can use the service GoogleAdsService. Question Find customers who have never made an order. id ORDER BY Orders. 2019' Im struggling to find the correct query for this. The fiscal year starts two months after the calender year and therefore goes from March to February. Provide details and share your research! But avoid Asking for help, clarification, or responding to other answers. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I would like to get all the customers that bought a Toaster, unless they also bought a breadbox. 2. c_id from orders o join shops s on o. CustomerDao dao = new CustomerDao(); you are out of Spring context too, you can't instantiate it with the new keyword, it must be injected by Spring, that's why your sessionFactory is null. All joins should have an ON clause, not a WHERE clause for the JOIN conditions. So select all customer emails that don't feature at all in previous months. if an orderid has an order rank of 2 the order in question was the customer’s second consecutive order since their registration. Category A: 1. Category C: 3. So another disadvantage what I expect would be the maintenance of multiple connections at the same Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; when no customer group is selected it must give me names, phones and emails for all customers in the store. branchNumber WHERE NOT EXISTS (-- all branch numbers that Adam Rivera owns (SELECT b2. I want to find out customers who got created in the last X minutes. Order_rank contains a count of a customer’s successful orders - e. The endpoint i am looking for is a /Customer/list that can retrieve our customers with a subscription status : trial - active - done for example. accNumber = o1. But I am getting an error: Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; Then you just remove them from all customers. and keep them completely independent. all customer_i_need = customers. Actually I want to calculate All Customers Account Receivables. Goal of the query: Get list of Customer who have bought all the items from their Wishlist? I have 2 tables and the fields as given below, Customer_Orders : Customer_ID, Order_ID, Order_date, Product_ID, email. All Microsoft Graph API permission: Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; using c#, I need to get all Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; It might be worth changing title of this question to something more specific like "DB design: one large DB for all customers or many small DB. Commented Dec 4, 2016 at 7:06. blvl is the level for the prices 1-8 stored in this lvlholder customer. Since the frequency will be the entire time frequency of that month's customers instead of their monthly frequency, I'm thinking of writing a query where I change the date to find the outcome for each month. branchNumber = a1. I have code that loops through the pulls all the data from the source account. I now want to Display all the customers that haven't bought anything in the month July or August. From the perspective of app, you may decide to use some queue mechanism. SELECT SUM(items. ItemName = 'spoon' THEN 1 Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; So I'm getting all the cancelled customers from the first table, then running those through the second table to count each order that has For each customer, I want to return: id, name, address, city, cap, country and total of orders. For example, Customers comprise of Business A, Business B and Business C. customer accounts, settings, templates, etc. starting_after. M and N can be relatively big, so I have cases with more than 40,000 square cells overall. lastName, c1. ordNum FROM customers c -- Parsing the XML for customers should be pretty straightforward, but parsing the individual tasks/jobs for each customer will be laborious, because there are no subnodes for each task - basically you get repeating chunks of XML with all the basic customer info (address, billing address, shipping address, etc. ) Now I've got in the invoice table customer_key. id, customer_client. sql; oracle-database; Share. manager, customer_client. – Jonathan Fite. As Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Now I want to find all customers who have both an account and a loan at the Perryridge branch. A query that would only return Jack. For example Customer_01 appears the first time on 2020-03-18 within the fiscal year 2020-03 til 2021-02. list(customer: CUSTOMER_ID) Original Answer. order_product name order_product quantity order_product name order_product quantity etc. SELECT cust#, name, city, industry-type FROM customer INNER JOIN order ON Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I need to select all NEW customers for the month of March. (e. name, count(o. Search, you can get account level info using the following GAQL query:. ) as well. Both tables have a 'status' field, in tblclients it is either 'active' or 'inactive' and in tblservices it is either 'active' or 'terminated'. I have a number of customers Z distributed in this grid, some cells will contain many customers while others will be empty. The following retrieves all invoices: customer. order. Example: In jan i have 20 new customers; In feb i have 5 new customers; In Mar i have 10 new customers. ON c. java class is not Spring maintained, so the injection of CustomerDao does not work. firstName, cr. I am specifically interested to know the exact header value to use for created. EDIT2: Using EXCEPT (SQL Server): That is the old-style JOIN syntax, wherein (+) denotes an OUTER JOIN. ItemName = 'knife' THEN 1 END) > 0 THEN 'Y' ELSE 'N' END AS Knife, CASE WHEN COUNT(CASE WHEN i. I have a transactions table that contains customer names and the company they did business. GMB. I need to write a SQL statement which will output a list of active clients which The MONTH(NOW() should have a closing bracket i. com. I want to find customers that have at least 5 transactions on At most three consecutive days For ex Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; I have two tables: Customers and Orders. customers_id = o. It offers easy pagination handling and rate limiting. NAME, o. Each customer will have many users. I used to get information about the user from Order information like this: class VivasIndustries_SmsNotification_Model_Observer { public I suspect that your test. If you don't have it, create it. for getting 250 data from shopify api we can use limit but pagination and synchronization for getting all data we need some step to get If Customer_T is a table in which all your customer information lies (such that a customer state would not exist there without a customer), then you need no WHERE clause. The database table has about 100k rows, and I'm looking for an efficient query. user7754371 user7754371. For instance, if you make a list request and receive 100 objects, ending with obj_foo, your subsequent call can include starting_after=obj_foo in order to fetch the next page Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; I have this function that tries to retrieve all the customer's emails in stripe: The LEFT JOIN keeps all customers, even those without orders. Orders: You can retrieve all orders for a customer with the list all orders method and the customer parameter. loan_number = loan. A customer is able to add multiple credit cards of bank accounts if he Products OverflowAI; Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product For a private Shopify app, I want to retrieve all the customers data and write into a csv file. In this particular issue, I have an imaginary city divided into squares - basically a MxN grid of squares covering the city. But after some study understand the whole way to solve. I can't seem to figure this out! Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question. select do |c| c. all The following retrieves all invoices for the customer only: customer. I am trying to make this query, because my bigger goal is to iterate over all customers and their last orders to get crucial It depends on whether the customers are tightly or loosely related to one another. I don't want to group or count the invoices, I actually need to see all invoices. order_id name quantity Is this a known behavior that ListCustomers does not return all customers? EDIT: Doing a little more digging, I found that Square separates customers into those "created by Square" and those "created by you". Commented Apr 17, 2024 You can indeed use a having clause to ensure that the given customer has all their items expired. . Customers do not have to register to order, so I'm working simply with the customer email and the date time of the order. The output would look something like this: I am trying to run simple query to get list of all customers staying in same city. mysql; sql; Share. s_company) = max(s. I would like to find a way to place Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; Given two table customers and orders, how to find all cusomers who didn't place an order. Therefore, this Meaning each customer installs own webshop source files, php. starting_after is an object ID that defines your place in the list. Basically, you would validate all, if they don't pass, throw the exception, or other validation failed events, with the customer(s) that did not pass using an identifier or the actual objects. – I would like to have a list like: 10 customers made 0 orders 4 customers made 1 order 5 customers made 2 orders 2 customers made 3 orders and so on. To determine from the recurring customers (customers frequently making different transactions), who all are also bulk customers. SELECT first_name from customers I need to show 'All customers that have NOT placed an order within a specific year, i. id_customer=Customers. firstname lastname. lastname FROM Orders INNER JOIN Customers ON Orders. bhsjc whzpq skfo zua wzjv vkndd uuqb pkc lsfy zuhafkh